Skip to main content

Current Units

Electrical current is the flow of electrons. Together with voltage, it determines the power consumed by compressors.

What is Current?​

Current (II) is the amount of electrical charge flowing per second. Think of it as:

  • Water flow rate in a pipe → Current in a wire
  • Higher flow = more water per second
  • Higher current = more electrons per second

Current Units​

UnitSymbolEquivalence
Ampere (Amp)ABase unit
MilliamperemA0.001 A
KiloamperekA1,000 A

Current in Compressors​

Rated Current vs Starting Current​

TypeDescriptionTypical Value
FLA (Full Load Amps)Current at full loadNameplate value
LRA (Locked Rotor Amps)Starting current5-8× FLA
RLA (Running Load Amps)Actual operating current80-100% FLA
Caution

Starting current can be 6-8 times higher than rated current:

Istarting=6×IratedI_{starting} = 6 \times I_{rated}

This affects cable and protection sizing.

Typical Currents by Power (480V Three Phase)​

PowerApproximate Current
5 HP7 A
10 HP14 A
25 HP34 A
50 HP65 A
100 HP124 A
200 HP240 A

Power Factor​

Not all current does useful work:

Preal=V×I×cos⁡ϕ×3P_{real} = V \times I \times \cos\phi \times \sqrt{3} Papparent=V×I×3P_{apparent} = V \times I \times \sqrt{3} PF=PrealPapparent=cos⁡ϕPF = \frac{P_{real}}{P_{apparent}} = \cos\phi
Power FactorMeaning
1.0Ideal - all current is useful
0.85-0.95Typical for loaded motors
0.5-0.7Underloaded motor or problems
Improve PF

A low power factor means you pay for current that doesn't do work. Capacitor banks can correct it.

Ohm's Law​

The fundamental relationship between voltage, current, and resistance:

V=I×RV = I \times R

Where:

  • VV = Voltage (Volts)
  • II = Current (Amps)
  • RR = Resistance (Ohms)

Current Measurement​

Clamp Meter​

Essential tool for compressor diagnostics:

MeasurementIndicates
High currentOverload, damaged bearings, low voltage
Low currentUnderload, faulty valves
Unbalanced currentPhase or motor problem
Fluctuating currentMechanical problem

Current Imbalance​

In three-phase systems, all three phases should have similar current:

Imbalance (%)=Imax−IaverageIaverage×100\text{Imbalance (\%)} = \frac{I_{max} - I_{average}}{I_{average}} \times 100
ImbalanceStatus
< 10%Acceptable
10-20%Problematic
> 20%Critical

Overcurrent Protection​

DeviceFunction
FusesShort circuit protection
BreakersOverload protection
Thermal relayMotor protection
Motor protectorIntegral protection