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Heat Recovery

A conventional air compressor converts approximately 85-94% of electrical energy into heat. This heat is normally wasted to the atmosphere. Heat recovery captures this energy for useful purposes.

The Potential​

Compressor Energy Balance​

Energy balance diagram for an air compressor, illustrating how most electrical energy is converted into recoverable waste heat

For every 100 kW consumed by a compressor, only 4 kW converts to useful work. The remaining 96% dissipates as heat — energy that, without a recovery system, is lost entirely.

Available Energy​

Compressor SizeAvailable HeatEquivalent
50 HP (37 kW)120,000 BTU/hHeat 2,700 ft²
100 HP (75 kW)240,000 BTU/hHeat 5,400 ft²
200 HP (150 kW)480,000 BTU/hPreheat boiler
500 HP (375 kW)1.2 MMBTU/hIndustrial process

Heat Sources​

Lubricated Compressor​

┌─────────────────────────────────────────────────────────┐
│ LUBRICATED COMPRESSOR │
│ │
│ Inlet air ────────────────────────────────► Air │
│ 77°F Compression discharge │
│ ↓ 185°F │
│ ┌───────────┐ ↓ │
│ │ │ Aftercooler │
│ │ Oil │ ◄─────── ↓ │
│ │ 176-212°F│ Condensate │
│ │ │ │
│ └─────┬─────┘ │
│ │ │
│ Oil cooler │
│ │ │
│ ┌─────▼─────┐ │
│ │RECOVERABLE│ ◄── 80-90% of input │
│ │ HEAT │ energy │
│ └───────────┘ │
└─────────────────────────────────────────────────────────┘

Heat Location​

Source% of Total HeatTemperature
Oil72-80%176-212°F
Aftercooler10-15%104-122°F
Motor4-8%104-140°F
Radiation2-4%-

Applications​

1. Space Heating​

Winter:                            Summer:

┌─────────────┐ ┌─────────────┐
│ Compressor │ │ Compressor │
└──────┬──────┘ └──────┬──────┘
│ │
┌─────▼─────┐ ┌─────▼─────┐
│ Hot air │ │ Air to │
│ duct │ │ outdoors │
└─────┬─────┘ └───────────┘
│
┌─────▼─────┐
│ Workspace │
│ │
└───────────┘

Typical ROI: 6-18 months

2. Water Preheating​

                    ┌─────────────────────┐
│ Plate heat │
Hot oil ════════│ exchanger │════════► Oil
194°F │ │ cooled
│ ┌─────────────┐ │
│ │ │ │
Cold water ─────│───│ │───│──────► Hot water
59°F │ │ │ │ 140-158°F
│ └─────────────┘ │
└─────────────────────┘

Applications:

  • Process water
  • Boiler preheat
  • Domestic hot water
  • Industrial washing

3. Industrial Processes​

ProcessTemperatureApplication
Drying122-176°FWood, grain, paint
Washing104-140°FParts, bottles
Tank heating104-158°FChemicals, food
Thawing104-122°FFood products

Recovery Systems​

Air Recovery​

The simplest method:

                Compressor
│
┌─────┴─────┐
│ Fan │
│ │ │
│ ▼ │
│ ┌───────┐ │
│ │Radiator│ │
│ └───┬───┘ │
└─────┼─────┘
│
┌──────────┼──────────┐
│ │ │
Damper Damper Damper
winter summer mix
│ │ │
▼ ▼ ▼
To space To outdoors Proportional
ComponentFunction
Winter damperDirects hot air indoors
Summer damperExhausts hot air outdoors
Mix damperTemperature control
ThermostatAutomatic control

Water Recovery​

                      ┌──────────────────┐
│ Oil/water heat │
Oil ══════════════│ exchanger │══════════════► Oil
185°F │ │ 122°F
│ ┌──────────────┐ │
│ │ │ │
Water ────────────│─│ │─│────────────► Water
inlet 59°F │ │ │ │ outlet 158°F
│ └──────────────┘ │
└────────┬─────────┘
│
Water pump

Components:

  • Plate heat exchanger (oil/water)
  • Circulation pump
  • Control valve
  • Storage tank (optional)

Calculations​

Recoverable Energy​

Q=kWcompressor×ηrecovery×hours×3,412 BTU/kWhQ = kW_{\text{compressor}} \times \eta_{\text{recovery}} \times \text{hours} \times 3{,}412 \text{ BTU/kWh}

Where:

  • QQ = Recoverable energy (BTU/year)
  • η\eta = Recovery efficiency (0.5-0.9)

Example:

  • Compressor: 100 HP (75 kW)
  • η\eta: 70%
  • Hours: 8,000/year
Q=75×0.70×8,000×3,412=1,433 MMBTU/year=420,000 thermal kWh/yearQ = 75 \times 0.70 \times 8{,}000 \times 3{,}412 = 1{,}433 \text{ MMBTU/year} = 420{,}000 \text{ thermal kWh/year}

Economic Savings​

Savings=Q×Fuel costBoiler efficiency\text{Savings} = \frac{Q \times \text{Fuel cost}}{\text{Boiler efficiency}}

Example:

  • Q=1,433Q = 1{,}433 MMBTU/year
  • Natural gas: $10/MMBTU
  • Boiler efficiency: 80%
Savings=1,433×100.80=$17,912/year\text{Savings} = \frac{1{,}433 \times 10}{0.80} = \$17{,}912\text{/year}

Typical ROI​

SystemInvestmentAnnual SavingsPayback
Air ducts (simple)$2,000-5,000$3,000-8,0006-12 months
Potable water$5,000-15,000$5,000-15,00012-18 months
Industrial process$10,000-50,000$15,000-60,00012-24 months
Integrated system$20,000-100,000$30,000-150,00018-36 months

Considerations​

Limitations​

FactorImpact
Variable heat demandMay not coincide with operation
Distance to useTransport losses
Required temperatureLimit ~158°F for water
Summer operationNo heating demand

Requirements​

SystemRequirement
Heat exchanger spaceNear compressor
PipingInsulated
ControlThermostats, valves
MaintenancePeriodic cleaning
Quick Evaluation

If your plant spends more than $20,000/year on heating and has compressors larger than 50 HP operating more than 4,000 hours/year, heat recovery is probably cost-effective.